Cuesta College, San Luis Obispo, CA

(A) gravitational potential energy.
(B) translational kinetic energy.
(C) (Both of the above choices.)
(D) (Neither of the above choices.)
Correct answer (highlight to unhide): (C)
The change in translational kinetic energy is given by:
∆KEtr = (1/2)·m·(vf2 – v02).
Since the speed of the box is increasing, vf is faster than v0, and so KEtr is increasing (∆KEtr is positive).
The change in gravitational potential energy is given by:
∆PEgrav = m·g·(yf – y0).
Since yf is higher than y0, then PEgrav also increases (∆PEgrav is positive).
Sections 70854, 70855
Exam code: quiz04JuR4
(A) : 17 students
(B) : 7 students
(C) : 28 students
(D) : 0 students
Success level: 54%
Discrimination index (Aubrecht & Aubrecht, 1983): 0.75
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