20150930

Physics quiz archive: vectors, projectile motion, forces

Physics 205A Quiz 3, fall semester 2015
Cuesta College, San Luis Obispo, CA
Sections 70854, 70855, 73320, version 1
Exam code: quiz03re3T



Sections 70854, 70855, 73320 results
0- 6 :   * [low = 6]
7-12 :   *
13-18 :   *******************
19-24 :   ****************************** [mean = 22.4 +/- 4.9]
25-30 :   ********************** [high = 30]

20150917

Astronomy quiz archive: eclipses/history of astronomy

Astronomy 210 Quiz 2, fall semester 2015
Cuesta College, San Luis Obispo, CA

Section 70158, version 1
Exam code: quiz02s5Sz


Section 70158
0- 8.0 :  
8.5-16.0 :   ********** [low = 8.5]
16.5-24.0 :   *********** [mean = 23.1 +/- 8.2]
24.5-32.0 :   **************
32.5-40.0 :   ******* [high = 40.0]


Section 70160, version 1
Exam code: quiz02Nnz2


Section 70160
0- 8.0 :  
8.5-16.0 :   ******* [low = 9.0]
16.5-24.0 :   ********* [mean = 23.5 +/- 7.7]
24.5-32.0 :   ********
32.5-40.0 :   ***** [high = 36.0]

20150903

Astronomy quiz archive: stars/sun/seasons/moon phases

Astronomy 210 Quiz 1, fall semester 2015
Cuesta College, San Luis Obispo, CA

Section 70158, version 1
Exam code: quiz01sC4r


Section 70158
0- 8.0 :  
8.5-16.0 :   ****** [low = 9]
16.5-24.0 :   *******
24.5-32.0 :   ************ [mean = 29.0 +/- 9.2]
32.5-40.0 :   ******************** [high = 40]


Section 70160, version 1
Exam code: quiz01n35t


Section 70160
0- 8.0 :   *** [low = 0]
8.5-16.0 :   ****
16.5-24.0 :   ************ [mean = 22.9 +/- 9.8]
24.5-32.0 :   ******
32.5-40.0 :   ****** [high = 40]

20150902

Physics presentation: free fall

This is only just a little disturbing, but I can't stop watching this. (Movie link: "experiment with apples.")

So let's try to analyze this and similar types of motion--free fall--using graphs and equations from our one-dimensional motion toolbox.

Our working definition of free fall is an object that is subject only to the force of gravity. Nothing in contact with it, nor any drag (although we often make the assumption that drag forces are negligible).

So let's take a look at how the kinematic equations turn out for free fall motion.

We'll consider the convention where up is the positive vertical direction. (If you're the type that likes to call down positive, you're just being contrary and weird.) Since an object in free fall is only experiencing the force of gravity, then it will experience the acceleration due to gravity (of magnitude 9.80 m/s2), which is directed downwards, and thus requires an obligatory negative sign.

Note that our vertical motion equations will then have a vertical acceleration ay = –9.80 m/s2. Again, that obligatory negative sign (also we'll assume that the starting position is y0 = 0 m at t0 = 0 s).

Also the quadratic formula will often be useful as well for free fall.

Let's take a look at every conceivable vertical velocity vy vs. t graph there could possibly be for any type of free fall situation.

But don't worry, there are only three possible graphs. Notice that they have all have the same negative slope--and since the slope of a velocity versus time graph is acceleration, these graphs all have the same acceleration ay = –9.80 m/s2. The only difference between these graphs is the initial vertical velocity v0y, whether positive (thrown upwards), zero (and thus released from rest), or negative (and thus thrown downwards).

So let's take a look at some situations, and decide which free fall graph best describes them (assuming we can neglect drag).

A boy steps off of a ledge (with no initial vertical velocity) and splashes into the water below.
The vy(t) graph has __________ initial velocity v0y.
(A) a negative.
(B) zero.
(C) a positive.
(D) (Unsure/guessing/lost/help!)

The vertical distance traveled is __________ the magnitude of the vertical displacement.
(A) less than.
(B) equal to.
(C) greater than.
(D) (Unsure/guessing/lost/help!)

A ball is thrown and released downwards from the top of a building, and hits the ground below.
The vy(t) graph has __________ initial velocity v0y.
(A) a negative.
(B) zero.
(C) a positive.
(D) (Unsure/guessing/lost/help!)

The vertical distance traveled is __________ the magnitude of the vertical displacement.
(A) less than.
(B) equal to.
(C) greater than.
(D) (Unsure/guessing/lost/help!)

A hat is thrown and released upwards into the air and lands on the grass below.
The vy(t) graph has __________ initial velocity v0y.
(A) a negative.
(B) zero.
(C) a positive.
(D) (Unsure/guessing/lost/help!)

The vertical distance traveled is __________ the magnitude of the vertical displacement.
(A) less than.
(B) equal to.
(C) greater than.
(D) (Unsure/guessing/lost/help!)

Physics presentation: projectile motion

There is nothing more awesome than watching physics being applied successfully to the real-world. Make this a meme: APPLIED PHYSICS IS APPLIED. (Movie link: "DC SHOES: HOOPS COMMERCIAL.")

We'll analyze the principles behind this type of motion, and the equations used to analyze this motion.

Some working definitions: a projectile is an object that is subject only to the force of gravity once underway, and we'll consider the simplest (but not necessarily realistic) case where drag is negligible.

With these assumptions, then the trajectory--the path that this projectile travels along--has certain special properties.

Let's see how we can extend our previous understanding of objects moving vertically in free fall to projectile motion, and watch various examples of projectiles in motion.

If we shoot a ball vertically upwards, its upwards and subsequent downwards motion is only subject to the force of gravity (neglecting drag). This can be considered a special case of projectile motion.

Suppose that the cart that vertically launches the ball moves at a constant speed horizontally, here, along a smooth track.

When this horizontally moving cart launches a ball vertically...

...the ball will move along a trajectory...

...such that it will subsequently land back into the cart. This means that the horizontal motion of both ball and cart were always in sync, and that their horizontal motion is independent of the vertical motion of the ball. (Movie link: "110725-1240640-r.")

So projectile motion depends on two independent ingredients--vertical: free fall motion; horizontal: constant velocity motion.

If there is no horizontal motion, then projectile motion is the simple vertical free fall case. Here, stacking two anvils with a generous amount of gunpowder sandwiched between them results in...a vertical anvil trajectory. (Movie link: "Downieville Gold Rush Anvil Launch.")
Which initial velocity component(s) for the anvil (v0x, v0y) is/are zero? positive? Negative?
Which (constant) acceleration component(s) for the anvil (ax, ay) is/are zero? positive? Negative?
Driving a car off of a cliff results in another example of projectile motion, but remember that this is just vertical free fall, with the constant horizontal motion of the car's initial velocity as it drove off of the cliff. (Movie link: "Car Off Cliff.")
Which initial velocity component(s) for the car (v0x, v0y) is/are zero? positive? Negative?
Which (constant) acceleration component(s) for the car (ax, ay) is/are zero? positive? Negative?
Not content to drive a car off of a cliff, here a car is launched diagonally upwards, and then hit with an anti-tank rocket (which may or may not be a computer generated special effect). Again this is just vertical free fall, with constant horizontal motion. (Movie link: "Jeremy Clarkson - Hot Metal.")
Which initial velocity component(s) for the car (v0x, v0y) is/are zero? positive? Negative?
Which (constant) acceleration component(s) for the car (ax, ay) is/are zero? positive? Negative?
Hijinks aside, it's time to look at the boring but important equations that describe projectile motion.

Vertical motion is described with the same set of free fall equations that we have seen before.

With the sometimes necessary quadratic formula...

The only new equation here reflects the constant horizontal motion that goes on simultaneously with the vertical free fall motion. Since horizontal velocity never changes, horizontal acceleration is zero, so the only important equation is how horizontal displacement increases linearly with elapsed time.

So whereas we had five equations to describe vertical free fall motion, we only need one more equation--constant horizontal motion--to fully describe projectile trajectories.

Closing note--trajectory motion is merely vertical free fall, with an added horizontal velocity component: so two billiard balls released simultaneously, with one dropped from rest, the other with an initial horizontal velocity will have the same vertical motion, and must hit the floor at the same time. (Movie link: "Shoot-n-Drop.")