Cuesta College, San Luis Obispo, CA
Sections 70854, 70855
Exam code: quiz07VlnC


Sections 70854, 70855 results
| 0- 6 : | * [low = 3] |
| 7-12 : | ********** |
| 13-18 : | ************** |
| 19-24 : | ******************* [mean = 18.9 +/- 6.2] |
| 25-30 : | ******* [high = 30] |
Astronomy and physics education research and comments, think-pair-share (peer instruction) clicker questions, flashcard questions, in-class activities (lecture-tutorials), current events questions, backwards faded scaffolding laboratories, Hake gains, multiple-choice and essay exam questions, indices of discrimination, presentation slides, photos, ephemerae, astronomy in the marketplace, unrelated random sketches and minutiae.


| 0- 6 : | * [low = 3] |
| 7-12 : | ********** |
| 13-18 : | ************** |
| 19-24 : | ******************* [mean = 18.9 +/- 6.2] |
| 25-30 : | ******* [high = 30] |
A solid object is (a) partially submerged in water as it sinks with increasing speed, then while (b) completely underwater it still sinks with increasing speed. Discuss why the magnitude of the net force on the object is greater for case (a) than for case (b). Ignore friction and drag. Explain your reasoning using the properties of Newton's laws, Archimedes' principle (buoyant forces), and free-body diagrams. Weight force of Earth on block (downwards, magnitude w = m⋅g, same for both (a) and (b)),
Buoyant force of water on block (upwards, magnitude FB = ρ_water⋅g⋅Vsub, less for (a)); and

A solid block has 75% of its volume below water, while resting on the bottom of a water tank. The force with the largest magnitude is the: Weight force of Earth on block (downwards, magnitude w = m·g).Because the block is stationary in the vertical direction, from Newton's first law all of the up and down forces must sum to zero. This means that the two upwards forces (buoyant force and normal force) are together equal to the one downwards force (weight), such that the weight force has the largest magnitude of these three forces.
Buoyant force of water on block (upwards, magnitude FB = ρfluid·g·(Volume submerged)).
Normal force of tank bottom on block (upwards, magnitude N).



| 0- 6 :   | ** [low = 6] |
| 7-12 :   | ********* |
| 13-18 :   | *********** |
| 19-24 :   | ***************** [mean = 19.8 +/- 6.3] |
| 25-30 :   | ************* [high = 27] |

"Fluid flow can be steady or unsteady. Velocity at any point is constant as time passes for a steady flow. Unsteady flow exists whenever the velocity at a point in the fluid changes as time passes. Fluids can also be compressible or incompressible, most being nearly incompressible. Fluid flow can be viscous or nonviscous. A viscous fluid does not flow readily but a non-viscous one, like water, does."
"Ideal fluid flow has the following characteristics; incompressible, laminar, and non-viscous. I understand how volume flow rate conservation law that comes from its incompressible nature uses the continuity equation. And how the energy density conservation law uses Bernoulli's equation."
"Fluid flow can be steady or unsteady; Unsteady flow exists whenever the velocity at a point in the fluid changed as time passes, Turbulent flow is an extreme kind of unsteady flow and occurs when there are sharp obstacles or bends in the path of a fast moving fluid. Fluid can be compressible or incompressible, fluid flow can be viscous or non-viscous."
"I understand that when an ideal fluid flows through a pipe with a widening cross sectional area, the velocity of the fluid will slow down, kinetic energy decreases and the pressure will increase. When an ideal fluid flows through a pipe with a narrowing cross sectional area, the velocity of the fluid will increase, kinetic energy is increases and the pressure will decrease."
"As the area decreases the fluid speed increases. when elevation decreases the fluid speed also increases. Bernoulli's equation relates the density, pressure, fluid speed and elevation at two separate points."
"I seemed to understand this subject, but completely differentiating between the properties of ideal fluid flow will need more practice. What seemed somewhat confusing or a little more review in class are volume flow conservation and energy density conservation, and exactly how to apply the continuity equation to volume flow rate conservation law and the Bernoulli's equation to energy density conservation law."
"Bernoulli's equation definitely seems ominous. I can see the relation between energy conservation and this topic. However, hopefully after the homework problems I'll be more comfortable with it."
"I am confused about when to use Bernoulli's equation and how the concepts of the work-energy theorem relates to this equation. I am confused by what is meant by how elevation changes the various variables as well."
"I don't understand when the pressure or density changes, or how to know when y changes, how that works with/ against the change in area. I dont understand how to calculate anything, lost :("
"I didn't quite understand Bernoulli’s equation. The equations itself looked very complicated and when the book didn’t really provide an example problem and I feel like I just learn better that way so maybe that’s why I feel like I didn’t understand how to use the equation."
"This chapter seemed to hold a mess of equations that I don't know when to use or how to use them; however, it seems similar to the set-up of our previous conservation equations in which we ignore one side of the equation and can determine whether each piece on the right side of the equation is increasing or decreasing."
"How Bernoulli's equation relates to the work-energy theorem."
"I don't understand anything yet."
"m3/s."

decreases.   [0] remains constant.   **************************************** [40] increases.   **** [4] (Unsure/lost/guessing/help!)   ** [2]

decreases.   ************************* [25] remains constant.   ********* [9] increases.   ********** [10] (Unsure/lost/guessing/help!)   ** [2]

decreases.   ********** [10] remains constant.   ******* [7] increases.   *************************** [27] (Unsure/lost/guessing/help!)   ******* [2]

(1/2)·ρ·∆(v2): decreases [54%]
ρ·g·∆y: no change [52%]
∆P: increases [33%]

(1/2)·ρ·∆(v2): increases [57%]
ρ·g·∆y: no change [54%]
∆P: decreases [37%]

(1/2)·ρ·∆(v2): no change [89%]
ρ·g·∆y: decreases [33%]
∆P: increases [74%]
"If cross-sectional area is changing, do we assuming that particles are still moving in a straight line with no vertical deviation?" (Yes, if flow is laminar all the streamlines will be parallel to each other, either scrunching together or spacing apart without crossing. #whateveryoudodontcrossthestreams.)
"Great presentation GIFs. Super-helpful for understanding the material."
"Your drawings make everything better. shout out to visual learners."
"Go over these as you normally do, thank you!"
"Now you know why I don't want to be a physics major. I want to just live my life with plants and dirt."

"Mass density is mass of a substance divided by its volume."
"Pressure as force density is force divided by area. Pressure as energy density is energy divided by volume."
"The concept of pressure being force over surface area. As well as energy density conservation. If the surrounding pressure of an object increases then the ρ·g·∆y of the object will decrease and vice versa. As for the buoyant force, it's all dependent on the object's volume and the density of the fluid it is submerged in."
"That pressure and gravitational potential energy have an inverse relationship. So, for example, as a submarine goes further underwater in the y direction, its pressure increases while its gravitational potential energy decreases. The opposite is true for a balloon flying into the sky."
"In the example of a swimmer fully submerged underwater, I understand the application of Newton's first law in that all the forces acting on the swimmer balance out. This is given by the two forces of a downward weight force and upwards buoyant force balancing out."
"After going through the presentation preview, I was confused about the fluid density at first but then took another glance and realized that it is simply the kilograms divided by meters cubed because it is a 3D object it must be cubed."
"Something I didn't understand from the reading is pressure and depth in a static fluid. I don't understand the formula. I need an example of how to use it and what the variables mean."
"I was a little confused about the concept of buoyancy. I could definitely use some review of that equation."
"Archimedes' principle is a little confusing. When we draw our diagrams do we treat it as we would a normal force? Also, I feel like the book did a bad job at explaining some of this stuff. None of it seems too difficult by any means."
"The units and some equations that you use when looking at the problems. Hopefully will go over in class to clarify."
"101,325 Pa."
"1.013 × 105 Pa, which is also 1 atm."
"1,000 kg/m3."
"1.2 kg/m3."

ρair·g·∆y: increases [61%]
∆P: decreases [56%]

ρwater·g·∆y: decreases [44%]
∆P: increases [66%]

first; balanced. ******************************** [32] second; unbalanced. ****** [6] (Unsure/lost/guessing/help!) *** [3]
diver. *********** [11] water. *************************** [27] (Unsure/lost/guessing/help!) *** [3]

first; balanced. **************************** [28] second; unbalanced. ********** [10] (Unsure/lost/guessing/help!) *** [3]
seawater. *********************** [23] air. ** [2] red ship. ************ [12] (Unsure/lost/guessing/help!) **** [4]
underwater portion. *********************** [23] above water portion. ** [2] total volume, both underwater and above water. ************* [13] (Unsure/lost/guessing/help!) [3]
"Please go over these!"
"I would love if we could spend a generous amount of time calculating different pressures."
"Yikes! These were challenging for me. Hopefully I will feel better about this material after lecture."
"I do not understand the concept behind the red ship's buoyancy and I am having a hard time understanding the reasoning behind the formulas."
"Are we given the equations on the tests?" (Yes--you can see which equations were given on past quizzes and exams, so you wouldn't need to memorize those.)


| 0- 6 : | ** [low = 6] |
| 7-12 : | **** |
| 13-18 : | *********** |
| 19-24 : | ********************** [mean = 20.8 +/- 6.0] |
| 25-30 : | ************ [high = 30] |
A wooden cube is made by gluing ebony (denser) and balsa (less dense) pieces together. Both pieces have the same volume. The total density of the cube is less than that of water. The cube is carefully placed into water such that it floats "top-heavy" (ebony on top of balsa). The cube is then turned over such that it floats "bottom-heavy" (balsa on top of ebony). Discuss which orientation will float higher (or if there is tie), and why. (Ignore any water that may soak into the wood pieces, and the thin layer of glue between the two wood pieces.) Explain your reasoning using the properties of densities, volumes, forces, Newton's laws, Archimedes' principle (buoyant forces), and free-body diagrams. Weight force of Earth on block (downwards, magnitude w = m⋅g),and
Buoyant force of water on block (upwards, magnitude FB = ρwater⋅g⋅Vsub);

Water enters point [1] with a speed of 0.80 m/s. The pipe at point [2] is at a lower height than point [1], and has twice the cross-sectional area. Assume ideal fluid flow. The speed of the water at point [2] is:

| 0- 6 :   | |
| 7-12 :   | ******** [low = 9] |
| 13-18 :   | ************** |
| 19-24 :   | ************************* [mean = 19.6 +/- 5.2] |
| 25-30 :   | ***** [high = 30] |

"An ideal liquid is one that is in-compressible, non-viscous, and should undergo a laminar flow. The conservation laws regarding liquids allow us to determine several factors regarding liquids including volume and energy."
"The differences between compressible and non-compressible fluids which is kind of straight forward. Also the difference between non-viscous and viscous and between laminar and turbulent."
"An ideal fluid is incompressible, laminar, and non-viscous. Since it is incompressible, volume flow rate is conserved. Even when a pipe changes radius, the incompressibility of an ideal fluid means the same volume flowing in one end equals the same volume coming out the other end in the same time interval."
"I feel like I have a good grasp on the continuity equation. If the area of the 'in' is smaller than the area of the 'out,' then the speed will decrease on the way out. If the area for the 'in' is bigger than the 'out,' then the speed will increase on the way out."
"The volume flow rate of a fluid is defined to be the volume of fluid that is passing through a given cross sectional area per unit time. Because liquids are incompressible, any portion of liquid flowing through a pipe could change shape, but it must maintain the same volume. This is true even if the pipe changes diameter. In the diagram below [for the horizontal narrowing pipe] of liquid on the left changes shape as it enters a narrow section of pipe, but it maintains the same volume since liquids are incompressible."
"Sorry P-dog, but I'm still preparing for my art history midterm."
"I am kind of confused about Bernoulli's equation."
"I need help understanding Bernoulli's equation."
"I cannot seem to understand energy density conservation."
"I was confused why the equations have to balance out all the time."
"I need a better understanding of what each of the symbols represent in the equations. as well how to properly go about solving them."
"I found Bernoulli's equation a bit confusing. Mostly how gravitational potential energy density is affected by the cross-sectional area."
"I found the energy density conservation equations kind of confusing and would like to see examples of them worked out in lecture."
"Bernoulli's equation--I am not sure if the equation will always be balanced or if there are some cases where the right-hand side will not equal to 0."
"I think I understand why area and fluid speed increase, decrease, or are constant for given situations but I'm a little unsure when it comes to determining the values of each term in Bernoulli's equation. "
"I understand the difference between viscous and non-viscous liquids. I found everything else about this reading confusing."
"It all makes sense."
"I think I'm going to be okay right now."
"m3/s."
"Cubic meters per second."
"kg/s?"
"m/s2?"

decreases.   [0] remains constant.   *********************************************** [47] increases.   ** [2] (Unsure/lost/guessing/help!)   * [1]

decreases.   ******************** [20] remains constant.   *********************** [23] increases.   ****** [6] (Unsure/lost/guessing/help!)   * [1]

decreases.   ******* [7] remains constant.   ********************* [21] increases.   ********************* [21] (Unsure/lost/guessing/help!)   * [1]

(1/2)·ρ·∆(v2): decreases [58%]
ρ·g·∆y: no change [64%]
∆P: increases [52%]

(1/2)·ρ·∆(v2): increases [54%]
ρ·g·∆y: no change [56%]
∆P: decreases [54%]

(1/2)·ρ·∆(v2): no change [72%]
ρ·g·∆y: decreases [26%]
∆P: increases [18%]
"When you say water is incompressible to some extent, is that referring to ice?" (And liquid water, as well. This is why hydraulics work, as well as intravenous drips and hypodermic injections--push in here, stuff on the other side pushes out.)
"Is the flow rate with an ideal fluid always constant with the in and out?" (Yes, as ideally the fluid would be incompressible.)
"A little lost on the potential changes in kinetic, gravitational, pressure changes for the this last pipe with what appears to be no change in cross-sectional area, but a decrease in gravitational energy density." (That sounds pretty good, though.)
"I am a little confused on the descending pipe question and whether the pressure increases or decreases." (The pressure will increase, as the gravitational potential energy density decreases.)
"This is very difficult."
"I would like to go over these laws more in class."
"I don't understand the variables, but I believe that I will understand the concepts once we clarify each variable."
"Doing good so far."
"How do you have time to read 60+ comments?" (If I ask 60+ students to make time to answer questions and/or make comments on the reading assignments, then I have to make time to read them all. #becarefulofwhatyouwishfor)