Cuesta College, San Luis Obispo, CA

(A) vA.
(B) vB.
(C) (There is a tie.)
(D) (Not enough information is given.)
Correct answer (highlight to unhide): (B)
Since these θ angles are measured counterclockwise from the +x axis, the horizontal components of these velocity vectors are given by:
vA,x = vA·cosθA,
vB,x = vB·cosθB.
Then the horizontal components are these velocity vectors can be calculated and compared:
vA,x = vA·cosθA = (10 m/s)·cos(80°) = 1.736481776669303... m/s,
or to two significant figures, the horizontal component of vA has a magnitude of 1.7 m/s, while:
vB,x = vB·cosθB = (4.0 m/s)·cos(60°) = 2.0 m/s.
Thus the horizontal component of vB is greater than the horizontal component of the horizontal component of vA.
Sections 70854, 70855
Exam code: quiz03Ch3V
(A) : 4 students
(B) : 49 students
(C) : 1 student
(D) : 0 students
Success level: 91%
Discrimination index (Aubrecht & Aubrecht, 1983): 0.19
No comments:
Post a Comment