Cuesta College, San Luis Obispo, CA
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Solution and grading rubric:
- p:
Correct. Solves for the powers dissipated by each light bulb by:- finding equivalent resistance of the circuit by recognizing that the top light bulb is in series to the lower three parallel light bulbs);
- applying Ohm's law to determine the current of the equivalent circuit, which is the current flowing through the top light bulb;
- determines the power dissipated by the top light bulb;
- applies Kirchhoff's loop and/or junction rules to solve for the voltage difference used by and/or the current flowing through each of the lower three parallel light bulbs; and
- determines the power dissipated by each of the lower three parallel light bulbs.
- r:
Nearly correct, but includes minor math errors. Typically incorrect calculation in (1) or in (5), but otherwise everything else is consistent with this error. - t:
Nearly correct, but approach has conceptual errors, and/or major/compounded math errors. Multiple issues in (1)-(5), but still attempts to systematically analyze most of (1)-(5) even with wrong numerical values. - v:
Implementation of right ideas, but in an inconsistent, incomplete, or unorganized manner. Some attempt at applying Kirchhoff's rules, Ohm's law, and properties of electrical power. - x:
Implementation of ideas, but credit given for effort rather than merit. No clear attempt at applying Kirchhoff's rules, Ohm's law, and properties of electrical power. - y:
Irrelevant discussion/effectively blank. - z:
Blank.
Sections 30882, 30883
Exam code: midterm02u7aH
p: 10 students
r: 6 students
t: 7 students
v: 18 students
x: 2 students
y: 0 students
z: 0 students
A sample "p" response (from student 1982):
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Another sample "p" response (from student 8812):
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