Cuesta College, San Luis Obispo, CA
Polarized light passes through two polarizers with polarization axes turned as shown below.
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The total fraction of the incident light intensity transmitted through both polarizers is:
(A) 0.017.
(B) 0.063.
(C) 0.23.
(D) 0.87.
Correct answer (highlight to unhide): (A)
The fraction of the diagonally polarized light that passes through the polarizer 1 is cos2θ, where the angle θ = 75° is measured between the horizontal polarization of the light entering polarizer 1, and the transmission axis of polarizer 1 (15° clockwise from vertical). The light after passing through polarizer 1, but before passing through polarizer 2 is now diagonally polarized, having a polarization that matches the transmission axis of polarizer 1 (15° clockwise from vertical).
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The fraction of this diagonally polarized light that passes through polarizer 2 is again cos2θ, but where the angle θ = 60° is measured between the diagonal polarization of the light entering polarizer 2 (15° clockwise from vertical) and the transmission axis of polarizer 2 (15° counterclockwise from the horizontal).
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Thus the fraction of light that passes through both polarizer 1 and polarizer 2 is:
cos2(75°)·cos2(60°) = (0.067)⋅(0.25) = 0.017,
of the original unpolarized intensity, to two significant figures.
(Response (B) is cos2(75°)·cos2(15°); response (C) is cos2(15°)·cos2(60°); and response (D) is cos2(15°)⋅cos2(15°).)
Student responses
Sections 30882, 30883
Exam code: quiz01aN7u
(A) : 11 students
(B) : 12 students
(C) : 3 students
(D) : 11 students
Success level: 32%
Discrimination index (Aubrecht & Aubrecht, 1983): 0.25
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