Cuesta College, San Luis Obispo, CA
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Solution and grading rubric:
- p:
Discusses/demonstrates that the wavelength λ2 in the second n2 material would be longer than 533 nm by:- qualitatively or quantitatively showing that n2 < n1 by appealing to the critical angle θ2 = sin−1(n2/n1) (where n2 < n1 in order to avoid a domain error in the inverse sine function); or Snell's law n1⋅sinθ1 = n2⋅sinθ2 where θ2 = 90°, and thus n2 < n1; and
- that since index of refraction n = c/v, a smaller index of refraction n2 results in a faster speed of light v2; and
- since the wavelength λ = v/f, since the second material has a faster speed of light v2, and the frequency of light is independent of the medium it travels through, then it will have a longer wavelength in that material.
- r:
As (p), but argument indirectly, weakly, or only by definition supports the statement to be proven, or has minor inconsistencies or loopholes. Typically one of arguments (1)-(3) missing, incomplete, or problematic. - t:
Nearly correct, but argument has conceptual errors, or is incomplete. Typically two of arguments (1)-(3) missing, incomplete, or problematic. - v:
Limited relevant discussion of supporting evidence of at least some merit, but in an inconsistent or unclear manner. Some garbled attempt at applying Snell's law and/or critical angles, indices of refraction, wave speed, frequency and wavelengths. - x:
Implementation/application of ideas, but credit given for effort rather than merit. No clear attempt at applying Snell's law and/or critical angles, indices of refraction, wave speed, frequency and wavelengths. - y:
Irrelevant discussion/effectively blank. - z:
Blank.
Sections 30882, 30883
Exam code: midterm01cVdP
p: 17 students
r: 6 students
t: 9 students
v: 3 students
x: 0 students
y: 0 students
z: 0 students
A sample "p" response (from student 3673):
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A sample "p" response (from student 1929):
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