Astronomy quiz archive: sun/spectra/star properties

Astronomy 210 Quiz 5, spring semester 2018
Cuesta College, San Luis Obispo, CA

Section 30674, version 1
Exam code: quiz05NoPw


Section 30674

0- 8.0   :
8.5-16.0 :	* [low = 14.5]
16.5-24.0 :	*****
24.5-32.0 :	****** [mean = 27.6 +/- 7.1]
32.5-40.0 :	******* [high = 40.0]

Section 30676, version 1
Exam code: quiz05So1L


Section 30676

0- 8.0 :	**** [low = 4.0]
8.5-16.0 :	******
16.5-24.0 :	******
24.5-32.0 :	*************** [mean = 24.7 +/- 10.3]
32.5-40.0 :	*********** [high = 40.0]

Physics quiz archive: capacitors, circuits

Physics 205B Quiz 4, spring semester 2018
Cuesta College, San Luis Obispo, CA
Sections 30882, 30883, version 1
Exam code: quiz04Md1o



Sections 30882, 30883 results

0- 6 :
7-12 :	*** [low = 9]
13-18 :	************
19-24 :	************ [mean = 20.3 +/- 5.3]
25-30 :	***** [high = 27]

Physics midterm problem: diverging lens and converging lens

Physics 205B Midterm 1, spring semester 2018
Cuesta College, San Luis Obispo, CA

An object 1.0 cm in height is placed 5.0 cm in front of a f = –20.0 cm diverging lens, producing an upright image. This same 1.0 cm high object is then placed an unknown distance in front of a f = +20.0 cm converging lens, producing an inverted image that is the same size as the upright image originally produced by the diverging lens.

Determine (a) the size of the image produced by the diverging lens, and (b) the distance of this object in front of the f = +20.0 cm converging lens.

Show your work and explain your reasoning by using ray tracings and/or thin lens equations, properties of lenses, images, and magnification.

Solution and grading rubric:

• p:
  Correct. Identifies relevant parameters to methodically use the thin lens equation and linear magnification equation, in order to determine:
  1. that for the diverging lens, h_o = +1.0 cm, d_o = +5.0 cm, f = −20.0 cm, and uses thin lens equation to either find d_i = −4 cm (a virtual image) to find image height h_i = +0.8 cm (upright image) from the linear magnification equation, or may eliminate d_i in both equations to solve for h_i directly; and
  2. for the converging lens, h_o = +1.0 cm (the same object), d_o and d_i are both unknown, f = +20.0 cm, and h_i = −0.8 cm (inverted image that is the same size as the upright image produced by the diverging lens), and eliminates d_i in both equations to find d_o = +45 cm. May include very minor math errors with handling fractions and inverses.
• r:
  Nearly correct, but includes minor math conceptual errors, typically overlooking the fact that the image produced by the converging lens is inverted.
• t:
  Nearly correct, but approach has conceptual errors, and/or major/compounded math errors. At least solves for (1) successfully, and still attempts to methodically use this information in (2) to solve for the object distance for the converging lens. Typically makes multiple conceptual errors, such as overlooking the fact that the image produced by the converging lens is inverted; claiming that the image distance for the converging lens is the same as the image distance for the diverging lens, etc.
• v:
  Implementation of right ideas, but in an inconsistent, incomplete, or unorganized manner. Some garbled attempt at ray tracings and/or thin lens equations, the properties of lenses, images, and magnifications.
• x:
  Implementation of ideas, but credit given for effort rather than merit. No clear attempt at applying ray tracings and/or thin lens equations, the properties of lenses, images, and magnifications.
• y:
  Irrelevant discussion/effectively blank.
• z:
  Blank.
  

Grading distribution:
Sections 30882, 30883
Exam code: midterm01cVdP
p: 4 students
r: 7 students
t: 24 students
v: 0 students
x: 0 students
y: 0 students
z: 0 student

A sample "p" response (from student 7164):

Astronomy midterm question: Saturn high overhead at sunrise, then eventually at midnight?

Astronomy 210 Midterm 1, spring semester 2018
Cuesta College, San Luis Obispo, CA

The following explanation was given on an online discussion board[*]:

Say Saturn is overhead at sunrise. After a few months, Earth will have moved faster in its orbit than Saturn such that Saturn will then be visible overhead at midnight.

Discuss why this answer is correct for an observer in San Luis Obispo, CA, and how you know this. Support your answer using diagrams showing the positions of the sun, Saturn, Earth, and an observer on Earth.

[*] answers.yahoo.com/question/index?qid=20180302021141AAdHysp.

Solution and grading rubric:

• p:
  Complete diagram and reasoning includes the following explanations for an observer on Earth looking at Saturn:
  1. Saturn's position in its orbit around the sun is "ahead of" Earth's position in its orbit around the sun such that the observer on Earth at sunrise is able to see Saturn overhead; and
  2. a few months later, Earth has "caught up" to Saturn and they are (approximately) "lined up" with the sun (superior conjunction), such that the observer on Earth at midnight is able to see Saturn overhead.
• r:
  Nearly correct (explanation weak, unclear or only nearly complete); includes extraneous/tangential information; or has minor errors. Draws both diagrams: one correct, the other with slight errors.
• t:
  PContains right ideas, but discussion is unclear/incomplete or contains major errors. Draws both diagrams with errors; or has one diagram correct, the other missing/problematic.
• v:
  Limited relevant discussion of supporting evidence of at least some merit, but in an inconsistent or unclear manner. Some attempt at one diagram, with errors; the other is missing or effectively missing.
• x:
  Implementation/application of ideas, but credit given for effort rather than merit.
• y:
  Irrelevant discussion/effectively blank.
• z:
  Blank.

Grading distribution:
Section 30674
Exam code: midterm01nND4
p: 11 students
r: 2 students
t: 8 students
v: 2 student
x: 2 students
y: 0 students
z: 0 students

A sample "p" response (from student 4387):

Physics quiz archive: interference, electrostatics

Physics 205B Quiz 3, spring semester 2018
Cuesta College, San Luis Obispo, CA
Sections 30882, 30883, version 1
Exam code: quiz03Ch4R



Sections 30882, 30883 results

0- 6 :
7-12 :	** [low = 9]
13-18 :	****
19-24 :	************ [mean = 23.3 +/- 4.9]
25-30 :	************** [high = 30]

Astronomy quiz archive: telescopes

Astronomy 210 Quiz 3, spring semester 2018
Cuesta College, San Luis Obispo, CA

Section 30674, version 1
Exam code: quiz03nT7a

Section 30674

0- 8.0 :	** [low = 4.0]
8.5-16.0 :	****
16.5-24.0 :	***** [mean = 24.0 +/- 10.2]
24.5-32.0 :	*****
32.5-40.0 :	******* [high = 40.0]

Section 30676, version 1
Exam code: quiz03sB1g

Section 30676

0- 8.0 :	**** [low = 4.0]
8.5-16.0 :	*****
16.5-24.0 :	*********** [mean = 23.7 +/- 9.1]
24.5-32.0 :	*************
32.5-40.0 :	******* [high = 40.0]