Cuesta College, San Luis Obispo, CA
Polarized light passes through two polarizers with polarization axes turned as shown below.
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The total fraction of the incident light intensity transmitted through both polarizers is:
(A) 0.
(B) 0.19.
(C) 0.38.
(D) 0.56.
Correct answer (highlight to unhide): (B)
The fraction of the diagonally polarized light that passes through the vertical polarizer 1 is cos2θ, where the angle θ = 60° is measured between the diagonal polarization of the light entering polarizer 1 (60° clockwise from vertical) and the transmission axis of polarizer 1 (vertical). The light after passing through polarizer 1, but before passing through polarizer 2 is now vertically polarized, having a polarization that matches the transmission axis of polarizer 1.
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The fraction of this vertically polarized light that passes through polarizer 2 is again cos2θ, but where the angle θ = 30° is measured between the polarization of the light entering polarizer 2 (vertical) and the transmission axis of polarizer 2 (30° counterclockwise from the vertical).
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Thus the fraction of light that passes through both polarizer 1 and polarizer 2 is:
cos2(60°)·cos2(30°) = (1/4)⋅(3/4) = (3/16) = 0.1875,
or to two significant figures, 0.19 of the original unpolarized intensity.
(Response (C) is (1/2)·cos2(30°), which would be the fraction of unpolarized light that would pass through both polarizers; and response (D) is cos2(30°)⋅cos2(30°).)
Student responses
Sections 30882, 30883
Exam code: quiz01AM0l
(A) : 4 students
(B) : 25 students
(C) : 5 students
(D) : 1 student
Success level: 71%
Discrimination index (Aubrecht & Aubrecht, 1983): 0.45
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