Cuesta College, San Luis Obispo, CA
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The rotational inertia of the ring is __________ the rotational inertia of the solid disk.
(A) less than.
(B) equal to.
(C) greater than.
(D) (Not enough information is given.)
Correct answer (highlight to unhide): (C)
The rotational inertia of the ring of mass M = 1.2 kg and radius R = 0.25 m is:
Iring = M·R2 = (1.2 kg)·(0.25 m)2 = 0.075 kg·m2.
The rotational inertia of the disk of mass M = 1.2 kg and a radius smaller than 0.25 m, along with the factor of (1/2) then must be smaller than the rotational inertia of the ring:
Idisk = (1/2)·M·R2 = (1/2)·(1.2 kg)·(some value less than 0.25 m)2,
such that Iring > Idisk.
Sections 70854, 70855
Exam code: quiz05nWaW
(A) : 6 students
(B) : 4 students
(C) : 39 students
(D) : 0 students
Success level: 80%
Discrimination index (Aubrecht & Aubrecht, 1983): 0.34
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