Cuesta College, San Luis Obispo, CA
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(A) gravitational potential energy.
(B) translational kinetic energy.
(C) (Both of the above choices.)
(D) (Neither of the above choices.)
Correct answer (highlight to unhide): (B)
The energy transfer-balance equation is given by:
Wnc = ∆KEtr + ∆PEgrav + ∆PEelas,
where ∆PEelas = 0, as there is no spring involved in this process.
Just looking at the two remaining terms on the right-hand side of the energy transfer-balance equation, for the change in translational kinetic energy:
∆KEtr = (1/2)·m·(vf2 – v02),
and since the speed is constant, v0 and vf have the same magnitude, then KEtr is constant (∆KEtr = 0).
Also for the change in gravitational potential energy:
∆PEgrav = m·g·(yf – y0),
and since yf is greater than y0, then PEgrav increases (∆PEgrav is positive).
Sections 70854, 70855, 73320
Exam code: quiz04th1R
(A) : 6 students
(B) : 37 students
(C) : 5 students
(D) : 3 students
Success level: 73%
Discrimination index (Aubrecht & Aubrecht, 1983): 0.64
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