Cuesta College, San Luis Obispo, CA

(A) –67 m/s.
(B) –80 m/s.
(C) –88 m/s.
(D) –1.4×102 m/s.
Correct answer (highlight to unhide): (A)

v0x = v0·cosθ,
v0y = v0·sinθ.
Then the vertical component of the initial velocity vector is then:
v0y = v0·sinθ,
v0y = (105 m/s)·sin(320°) = –67.4926990171 m/s,
or to two significant figures, v0y = –67 m/s.
(Response (B) is (105 m/s)·cos(320°); response (C) is (105 m/s)·tan(320°); response (D) is (105 m/s)/cos(320°).)
Sections 70854, 70855, 73320
Exam code: quiz03sHO7
(A) : 30 students
(B) : 19 students
(C) : 7 students
(D) : 1 student
Success level: 53%
Discrimination index (Aubrecht & Aubrecht, 1983): 0.61
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