Cuesta College, San Luis Obispo, CA
The vx(t) graph of an object traveling in a straight line is shown at right. The object starts at x = 0 at t = 0. At t = 6 s, the acceleration is: (A) −2 m/s2.
(B) −1 m/s2.
(C) 0 m/s2.
(D) +1 m/s2.
(E) +2 m/s2.
Correct answer (highlight to unhide): (B)
The (instantaneous) acceleration at t = 6 s is the tangent slope of the vx(t) graph at that instant in time. Since the slope of the vx(t) graph is unchanged from t = 4 s to 9 s, then the average acceleration (given the chord slope) for that time interval will be identical to the instantaneous acceleration for any instant of time in that interval.
The average acceleration (which will be equal to the instantaneous acceleration) is then given by:
aav,x = chord slope = ∆vx/∆t = (−5 m/s)/(+5 s) = −1 m/s2.
Sections 70854, 70855
Exam code: quiz02Bo74
(A) : 2 students
(B) : 38 students
(C) : 4 students
(D) : 2 students
(E) : 12 students
Success level: 66%
Discrimination index (Aubrecht & Aubrecht, 1983): 0.46
No comments:
Post a Comment