Cuesta College, San Luis Obispo, CA
Cf. Giambattista/Richardson/Richardson, Physics, 2/e Problem 14.65
Department of Energy
wki.pe/File:Plutonium_pellet.jpg
An 8.0 kg sample of weapons-grade plutonium radiates approximately 70 watts[*]. The emissivity of plutonium is 0.55[**]. Assume that the environment is 273 K, and that the sample has a surface area of 0.026 m2. The temperature of the plutonium sample is:
(A) 550 K.
(B) 740 K.
(C) 820 K.
(D) 4,900 K.
[*] Theodore A. Parish, V. V. Khromov, and Igor Carron, eds., Safety Issues Associated With Plutonium Involvement in the Nuclear Fuel Cycle, Kluwer (1999), p. 81, goo.gl/3XRE5C.
[**] Thermophysical Properties of Materials for Nuclear Engineering: A Tutorial and Collection of Data, International Atomic Energy Agency (2008), p. 36, www-pub.iaea.org/MTCD/publications/PDF/IAEA-THPH_web.pdf.
Correct answer (highlight to unhide): (A)
The power (rate of heat per time) radiated is given by:
Power = –e·σ·A·((Tobj)4 – (Tenv)4),
where a negative value for power (here, "–70 watts") corresponds to a net amount of heat being removed (radiated) from the object, while a positive value corresponds to a net amount of heat being put into (absorbed) by the object (in order to be consistent with the ±Q convention for removing heat from (–) or putting heat into (+) a thermodynamic system). Solving for the temperature Tobj of the plutonium sphere:
((–Power/(e·σ·A)) + (Tenv)4))(1/4) = Tobj,
such that:
Tobj = ((–(–70 watts)/((0.55)·(5.670×10–8 watts/(m2·K4))·(0.026 m2)) + (273 K)4)(1/4),
Tobj = (+8.6333419667×1010 K4 + 0.5554571841×1010 K4)(1/4),
Tobj = (9.1887991508×1010 K4)(1/4),
Tobj = 550.5727209 K,
or to two significant figures, the temperature of the plutonium sphere is 550 K.
(Response (B) is (Power/(σ·A))(1/4) + Tenv; response (C) is (Power/(e·σ·A))(1/4) + Tenv; response (D) is Power/(e·A).)
Sections 70854, 70855, 73320
Exam code: quiz07b0o7
(A) : 28 students
(B) : 13 students
(C) : 16 students
(D) : 2 students
Success level: 47%
Discrimination index (Aubrecht & Aubrecht, 1983): 0.54
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