Physics 205B Quiz 2, spring semester 2012
Cuesta College, San Luis Obispo, CA
Cf. Giambattista/Richardson/Richardson, Physics, 2/e, Problem 24.51
A telescope has an eyepiece with a focal length of +2.0 cm, and the distance between the objective lens and eyepiece is 24.0 cm. The angular magnification of this telescope is:
(A) –48×.
(B) –13×.
(C) –12×.
(D) –11×.
Correct answer (highlight to unhide): (D)
The far focal point of the objective lens coincides with the near focal point of the eyepiece, such that the lens-to-lens distance L of the telescope is the sum of the objective and eyepiece focal lengths:
L = fobjective + feyepiece,
24.0 cm = fobjective + 2.0 cm,
where the objective lens focal length is then fobjective = +22.0 cm. Thus the angular magnification is given by:
M = –fobjective/feyepiece = –(22.0 cm)/(2.0 cm) = –11×.
(Response (A) is –fobjective·feyepiece; response (B) is (25.0 cm)/feyepiece; and response (C) is (24.0 cm)/feyepiece.)
Section 30882
Exam code: quiz02gL4s
(A) : 0 students
(B) : 4 students
(C) : 6 students
(D) : 14 students
Success level: 58%
Discrimination index (Aubrecht & Aubrecht, 1983): 0.57
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