Physics 205B Quiz 2, spring semester 2012
Cuesta College, San Luis Obispo, CA
Cf. Giambattista/Richardson/Richardson, Physics, 2/e, Problem 23.57
An image is located +7.0 cm (to the right) of a converging lens with a focal length of +5.5 cm. The object distance (to the left of the converging lens) is:
(A) +3.1 cm.
(B) +3.9 cm.
(C) +8.0 cm.
(D) +26 cm.
Correct answer (highlight to unhide): (D)
With the image distance di = +7.0 cm, and focal length f = +5.5 cm in the thin lens equation, the object distance do is:
(1/do) = (1/f) – (1/di),
such that:
do = +25.667 cm, or to two significant figures, +27 cm.
(Response (A) is (1/do) = (1/f) + (1/di); response (B) is (1/do); response (C) is 100/(f + di).)
Section 30882
Exam code: quiz02gL4s
(A) : 1 student
(B) : 3 students
(C) : 0 students
(D) : 20 students
Success level: 83%
Discrimination index (Aubrecht & Aubrecht, 1983): 0.67
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