Cuesta College, San Luis Obispo, CA
Cf. Giambattista/Richardson/Richardson, Physics, 2/e, Problems 9.27, 9.31
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(A) oil.
(B) water.
(C) (There is a tie.)
(D) (Not enough information is given.)
Correct answer (highlight to unhide): (A)
Both objects have the same weight force w (being the same volume and same density) downwards, but experience different upwards bouyant forces:
FB = ρfluid·g·Vsub.
Submerged volume is the same for either object, as they are both fully submerged, such that the bouyant force FB is greater for the object in water, as water has a greater fluid density ρfluid than oil.
From Newton's first law, since both objects are stationary, then the magnitude of the downwards weight force must be equal to the sum of the magnitudes of the upwards bouyant force and upwards normal force:
w = FB + N.
Since the weight force w is the same for both objects, and the bouyant force FB is larger for the object in water, then the normal force is larger for the object in oil.
Sections 70854, 70855
Exam code: quiz05t0rQ
(A) : 19 students
(B) : 12 students
(C) : 19 students
(D) : 0 students
(No response: 1 student)
Success level: 37%
Discrimination index (Aubrecht & Aubrecht, 1983): 0.72
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