Cuesta College, San Luis Obispo, CA
Cf. Giambattista/Richardson/Richardson, Physics, 2/e, Problem 18.74
Solution and grading rubric:
- p:
Correct. From application of Kirchhoff's loop rule, voltmeter reading would be either 15 V - (6.0 Ω)·I6, or (1.0 Ω)·I1, or (5.0 Ω)·I5, with I6, I1, and I5 being the currents going through the 6.0 Ω resistor, 1.0 Ω light bulb, and 5.0 Ω resistor, respectively. Correctly finds one (or all) of the currents in this circuit by use of equivalent resistance, Ohm's law, and Kirchhoff's junction rule, and uses current(s) to determine the voltmeter reading. - r:
Nearly correct, but includes minor math errors. - t:
Nearly correct, but approach has conceptual errors, and/or major/compounded math errors. At least finds equivalent resistance of circuit, and main current I6 = 2.2 A. - v:
Implementation of right ideas, but in an inconsistent, incomplete, or unorganized manner. - x:
Implementation of ideas, but credit given for effort rather than merit. - y:
Irrelevant discussion/effectively blank. - z:
Blank.
Grading distribution:
Section 31988
p: 4 students
r: 2 students
t: 3 students
v: 3 students
x: 1 student
y: 0 students
z: 0 students
A sample "p" response (from student 1230):
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