Cuesta College, San Luis Obispo, CA
Cf. Giambattista/Richardson/Richardson, Physics, 1/e, Problem 4.52
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Solution and grading rubric:
- p = 20/20:
Correct. Sets up Newton's first law for each of two situations (2.00 kg box sliding at constant speed; 2.00 kg + m2 boxes sliding at constant speed). Reduces these two equations to solve for the two unknowns μk and m2 (or eliminates μk to find only m2). May instead appeal directly to a ratio of 2.00 kg to (2.00 kg + m2), in relation to the ratio of kinetic friction forces in order to find the unknown mass. - r = 16/20:
Nearly correct, but includes minor math errors. As (p), but solves for the combined mass of (2.00 kg + m2), and not for the unknown mass m2 itself. - t = 12/20:
Nearly correct, but approach has conceptual errors, and/or major/compounded math errors. As (p), but uses Newton's second law, and eliminates acceleration common to both second law equations to find unknown mass. - v = 8/20:
Implementation of right ideas, but in an inconsistent, incomplete, or unorganized manner. May use work-energy conservation concepts. - x = 4/20:
Implementation of ideas, but credit given for effort rather than merit. - y = 2/20:
Irrelevant discussion/effectively blank. - z = 0/20:
Blank.
Grading distribution:
p: 18 students
r: 8 students
t: 2 students
v: 6 students
x: 0 students
y: 0 students
z: 1 student
A sample of a "p" response (from student 3153):
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Another sample of a "p" response (from student 8181), who sets up a free-body diagram and applies Newton's laws, and then applies proportional reasoning:
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One last "p" response (from student 1587), appealing directly to the ratio of forces and masses:
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