Physics quiz question: final speed of golf ball

Physics 205A Quiz 4, fall semester 2014
Cuesta College, San Luis Obispo, CA

Cf. Giambattista/Richardson/Richardson, Physics, 2/e, Problems 7.4, 7.13

"The Moment of Impact. An Inside Look at Titleist Golf Ball R&D"

A golf club[*] exerts a horizontal force of 8,900 N for 5.0×10–4 s on an initially stationary golf ball[**] (mass 4.593×10–2 kg). As a result of the impact with the golf club, the golf ball has a final speed of:
(A) 4.4 m/s.
(B) 97 m/s.
(C) 410 m/s.
(D) 910 m/s.

[*] real-world-physics-problems.com/physics-of-golf.html .
[**] wki.pe/Golf_ball.

Correct answer (highlight to unhide): (B)

The impulse exerted on the projectile is given by:

J = ∆p,

where the left side of the impulse-momentum theorem yields the impulse (directed to the right, in the positive +x direction):

J = (ΣF)·∆t = (+8,900 N)·(5.0×10–4 s) = +4.45 N·s,

of which only two figures are significant. The right side of the impulse-momentum theorem is the resulting change in momentum:

p = m·(vfv0) = (0.04593 kg)·((vf) – (0)),

p = (0.04593 kg)·vf.

By equating the left and right-hand sides of the impulse-momentum theorem with the known quantities entered, the final velocity of the golf ball can be solved for:

J = ∆p,

+4.45 N·s = (0.04593 kg)·vf,

+96.886566514 m/s = vf,

which is also directed to the right, in the positive +x direction, and the magnitude of the final velocity (or speed) of the golf ball, to two significant figures is 97 m/s.

(Response (A) is √(2g); response (C) is the magnitude of (ΣF·m; response (D) is the magnitude of (ΣF)/g.)

Student responses
Sections 30880, 30881
Exam code: quiz04w3Rc
(A) : 3 students
(B) : 54 students
(C) : 7 students
(D) : 1 student

Success level: 83%
Discrimination index (Aubrecht & Aubrecht, 1983): 0.57

No comments: