20150213

Physics quiz question: reflection, refraction at cocoa butter-Pyrex® interface

Physics 205B Quiz 1, spring semester 2015
Cuesta College, San Luis Obispo, CA

Cf. Giambattista/Richardson/Richardson, Physics, 2/e, Problem 23.11

"Cocoa Butter"
John (star5112)
flic.kr/p/Agns9

Light of wavelength 585 nm in melted cocoa butter (index of refraction[*] of 1.457) is incident at an angle of 60.0° at the interface between melted cocoa butter and Pyrex® (index of refraction[*] 1.474). (Drawing is not to scale.) As measured from the normal, the reflected angle in melted cocoa butter is __________ the transmitted angle in Pyrex®.
(A) less than.
(B) equal to.
(C) greater than.
(D) (There is no actual transmitted ray in Pyrex®.)
(E) (Not enough information is given.)

[*] physics.info/refraction/.

Correct answer (highlight to unhide): (C)

Snell's law relates the indices of refraction with the incident and transmitted angles:

ncocoa butter·sin(θcocoa butter) = npyrex·sin(θpyrex),

and the law of refraction relates the incident and (specularly) reflected angles in cocoa butter:

θincident = θreflected,

where the given (or assumed to be known) quantities, unknown quantities, and quantities to be explicitly solved for (or compared) are denoted.

From the law of reflection, the reflected angle in cocoa butter must also be 60.0°:

θincident = θreflected,

60.0° = θreflected.

From Snell's law, since the index of refraction for cocoa butter is greater than the index of refraction for Pyrex®, then the incident angle in cocoa butter must be smaller than the transmitted angle in Pyrex®. The transmitted angle in Pyrex® can also be solved for directly:

ncocoa butter·sin(θcocoa butter) = npyrex·sin(θpyrex),

(ncocoa butter/npyrex)·sin(θcocoa butter) = sin(θpyrex),

sin–1((ncocoa butter/npyrex)·sin(θcocoa butter)) = θpyrex,

sin–1((1.457/1.474)·sin(60.0°)) = θpyrex,

sin–1(0.85603732247) = θpyrex,

58.8745233263° = θpyrex,

and because the reflected angle in cocoa butter is 60.0°, and the transmitted angle in Pyrex® (to three significant figures) is 58.9°, then the reflected angle in cocoa butter is greater than the transmitted angle in Pyrex®.

Student responses
Sections 30882, 30883
Exam code: quiz01c0Co
(A) : 9 students
(B) : 11 students
(C) : 27 students
(D) : 1 student

Success level: 56%
Discrimination index (Aubrecht & Aubrecht, 1983): 0.32

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