Cuesta College, San Luis Obispo, CA
Cf. Giambattista/Richardson/Richardson, Physics, 2/e, Problem 16.25
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(A) 1.1×10–11 N.
(B) 1.4 N.
(C) 8.8×1010 N.
(D) (Not enough information is given.)
Correct answer (highlight to unhide): (B)
The magnitude of the force F experienced by a test charge q due to an electric field E is given by:
|Fon q| = |q·E| = |(–4.0×10–6 C)·(3.5×105 N/C)| = 1.4 N.
(Because the test charge is negative, the direction of the force exerted on it by the field (to the right) is opposite the direction of the field (to the left).)
Response (A) is |q/E|; response (C) is |E/q|.
Section 30882
Exam code: quiz03rD1o
(A) : 8 students
(B) : 16 students
(C) : 6 students
(D) : 2 students
Success level: 50%
Discrimination index (Aubrecht & Aubrecht, 1983): 0.44
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