Cuesta College, San Luis Obispo, CA
Cf. Giambattista/Richardson/Richardson, Physics, 2/e, Conceptual Question 23.8
A beam of light in Plexiglas® strikes the interface between Plexiglas® and olive oil, with an incident angle of 60.0°, and a transmitted angle of 61.2°. (Drawing is not to scale.) Light has a faster speed traveling through:
(B) olive oil.
(C) (There is a tie.)
(D) (Not enough information is given.)
Correct answer (highlight to unhide): (B)
Snell's law relates the indices of refraction with the incident and transmitted angles:
nplexiglas·sin(θplexiglas) = noil·sin(θoil),
and the indices of refraction for both materials related to the speed of light through them:
nplexiglas = c/vplexiglas,
noil = c/voil,
where the given (or assumed to be known) quantities, unknown quantities, and quantities to be explicitly solved for (or compared) are denoted.
From Snell's law, because θplexiglas is smaller than θoil, then nplexiglas is greater than noil. From n = c/v, since oil has a smaller index of refraction, it will have a faster speed of light. This can be explicitly seen by substituting the relations for each index of refraction into Snell's law, and relating the speed of light in oil to that in Plexiglas®:
(c/vplexiglas)·sin(θplexiglas) = (c/voil)·sin(θoil),
voil = vplexiglas·(sin(θoil)/sin(θplexiglas)) = vplexiglas·(sin(61.2°)/sin(60.0°) = 1.01187178523·vplexiglas,
Thus to the proper significant figures, the speed of light in oil is one percent faster than in Plexiglas®.
(A) : 5 students
(B) : 6 students
(C) : 0 students
(D) : 0 students
Success level: 55%
Discrimination index (Aubrecht & Aubrecht, 1983): 0.67