Cuesta College, San Luis Obispo, CA
Physics 8A learning goal Q7.2

(A) 1.11 kg.
(B) 1.54 kg.
(C) 2.49 kg.
(D) 26.5 kg.
(Cf. Young and Freeman, University Physics, 11/e, Problem 6.82.)
Correct answer: (C)
The decrease in gravitational potential energy of the unknown mass box is equal to the sum of the increases in kinetic energies of the 4.00 kg box and the unknown mass box. Thus if y_f = 0, then:
m_unknown = ((4.00 kg)*v_f^2)/(2*g*y_i – v_f^2) = 2.49 kg.
Note that setting the decrease in gravitational potential energy of the unknown mass box equal to the increase in kinetic energies of the 4.00 kg box only, where again y_f = 0, results in the incorrect response (B):
m_unknown = ((4.00 kg)*v_f^2)/(2*g*y_i) = 1.54 kg.
Student responses:
(A) : 2 students
(B) : 20 students
(C) : 9 students
(D) : 0 students
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