Physics 205B Quiz 6, spring semester 2019
Cuesta College, San Luis Obispo, CA
Cf. Giambattista/Richardson/Richardson, Physics, 2/e, Problem 20.34
The primary coil of a transformer has 400 turns; the secondary coil has 1,000 turns. An alternating current is sent through the primary coil with an input emf of 17 V. The output emf in the secondary coil is:
(A) 6.8 V.
(B) 10 V.
(C) 26 V.
(D) 43 V.
Correct answer: (D)
Given: N1 = 400 turns, N2 = 1,000 turns, and ε1 = 17 V.
Since ε2/ε1 = N2/N1 = I1/I2, then:
ε2 = ε1·(N2/N1) = (17 V)·(1,000/400) = 42.5 V,
which was expected to be higher than the input emf, as this is a step-up transformer (more turns in the secondary coil than the primary coil).
(Response (A) is ε1·(N1/N2); response (B) is ε1*(N2 – N1)/N2; response (C) is ε1·(N2 – N1)/N1.
Student responses
Sections 30882, 30883
Exam code: quiz06riQ1
(A) : 4 students
(B) : 1 student
(C) : 2 students
(D) : 31 students
Success level: 82%
Discrimination index (Aubrecht & Aubrecht, 1983): 0.25
Student responses
ReplyDeletePhysics 205B Quiz 6, spring semester 2010
Section 31988
Exam code: quiz06f7uX
(A) : 2 students
(B) : 0 students
(C) : 0 students
(D) : 11 students
Success level: 84%
Discrimination index (Aubrecht & Aubrecht, 1983): 0