Physics 205B Quiz 5, spring semester 2017
Cuesta College, San Luis Obispo, CA
The communication connection wire within a Type-C USB cable has a resistance of 5.6 kΩ, and while attached to a smartphone, 80 µA of current passes through this wire. While this current passes through the communication connection wire, the electrical power dissipated within it is:
(A) 1.4⨉10–8 W.
(B) 3.6⨉10–5 W.
(C) 0.45 W.
(D) 2.5⨉103 W.
[*] androidauthority.com/usb-type-c-and-3-1-explained-656552/.
Correct answer (highlight to unhide): (B)
Given the resistance R and the current I that passes through the communication connection wire, the voltage drop across it is given by Ohm's law:
∆V = I·R,
∆V = (80⨉10–6 A)·(5.6⨉103 Ω) = 0.448 V.
The power dissipated in the communication connection wire is then:
P = I·∆V,
P = (80⨉10–6 A)·(0.448 V) = 0.00003584 W,
or to two significant digits, 3.6⨉10–5 W.
Alternatively, the power can be directly calculated by making a substitution for ∆V using Ohm's law:
P = I·∆V = I·(I·R),
P = I2·R,
P = (80⨉10–6 A)2·((5.6⨉103 Ω) = 3.6⨉10–5 W.
(Response (A) is I/R; response (C) is ∆V = I·R; and response (D) is ∆V·R= I·R2.)
Sections 30882, 30883
Exam code: quiz05vLeY
(A) : 6 students
(B) : 17 students
(C) : 0 students
(D) : 3 students
Success level: 65%
Discrimination index (Aubrecht & Aubrecht, 1983): 0.86
No comments:
Post a Comment