Physics 205B Quiz 2, spring semester 2013
Cuesta College, San Luis Obispo, CA
Cf. Giambattista/Richardson/Richardson, Physics, 2/e, Problem 23.57
A f = +22 cm converging lens creates an upright image that is twice as large as the original object. The object distance is:
(A) +1.1 cm.
(B) +7.3 cm.
(C) +11 cm.
(D) +44 cm.
Correct answer (highlight to unhide): (C)
The linear magnification m equations can yield a relation between the object distance do and the image distance di:
m = hi/ho = –di/do,
where m = +2 (the positive sign denotes an upright image),
+2 = –di/do,
–2·do = di.
Solving for the location of the object do by eliminating di in the thin lens equation:
(1/do) + (1/di) = (1/f),
(1/do) + (1/(–2·do)) = (1/f),
(1/(2·do)) = (1/f),
do = f/2 = (+22 cm)/2 = +11 cm.
(Response (B) is one-third of the focal length; while response (D) is twice the focal length.)
Section 30882
Exam code: quiz02hYp0
(A) : 0 students
(B) : 3 students
(C) : 23 students
(D) : 7 students
Success level: 70%
Discrimination index (Aubrecht & Aubrecht, 1983): 0.67
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